CH3COOH + CH3CH2OH ⇄ ester + H2O
initial : 120·0,6/60 = 1,2 moli 46/46 = 1mol 44/88=0,5 (80+64)/18 =8
reactioneaza: x x
la echilibru : (1,2-x) (1-x) (0,5+x) ( 8 +x)
ms = 200 + 110 + 44 = 354g (0,5 + x)·44·100 / 354 = 17,41
0,5 + x = 1,4 x = 0,9 moli
Kc = [ester]·[H2O] / {[acid][alcool]
Kc = 1,4·8,9 /(0,3·0,1) Kc = 415,33