1/2(2x-1)+1/3(2x-1)+1/6(2x-1)=1

Răspuns :

[tex]^{3)} \frac{1}{2(2x-1)} + ^{2)} \frac{1}{3(2x-1)} + \frac{1}{6(2x-1)} =^{6(2x-1)} \frac{1}{1} \\3+2+1=6(2x-1)\\6(2x-1)=6\\2x-1=1\\2x=1+1\\2x=2\\x=1[/tex]
1 : 4x-2 +1: 6x-3+1: 12x-6=1
4x-2+6x-3+12x-6=1
22x-12=1